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Suppose you use an ideal pulley of the type shown in Figure 5.18(b) and find it...

Suppose you use an ideal pulley of the type shown in Figure 5.18(b) and find it necessary to exert a force of 300 N to support a load. Figure 5.18 (a) What is the load's mass? kg (b) What force is exerted on the ceiling? Neglect the pulley system's mass. N (upward)

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Answer #1

g = 9.8 m/s² and ignoring the slight angles which the rope makes with vertical

a) using the free body diagram of the lower pulley,
(It is given to you just to the right of the figure)
sum vertical forces to zero

3T - mg = 0
m = 3T/g
m = 3(300) / 9.8
m = 91.8 kg

b) let the force applied on the rope is downward
By using free body diagram of the upper two pulleys, sum vertical forces to zero.

F - 4T = 0
F = 1200 N

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