Question

How did my lecturer get the x values of x=0.00517 and x=-0.00588 using the quadratic formula?

xample What is the pli of a 00430 ml solution of nitrous acid, K708 x 1o initial change: equilibrium. 00430 0 0 ‘ assuming IH. from dissocialion of water is negligible, ()(430-x Strong acid 100 IHN2 00430 If the amount of HNO, that dissociates is small (e. << 00430), r-vA'a x 0,043() = 0.00552 mnol I, l. Check the approximation.(100)55200430s().I3üz'. I3% . which is not less than 5%) so you have to sole Ka x (0,0430-r) Weak aci Total concentration of acid 000517 or-00058s. Only the positive value makes sense pH log oH1-log 1o000517)-2.29

Answer 1