A small block with mass 0.221 kg is sliding down a frictionless ramp that is inclined...
A small block with mass 0.221 kg is sliding down a frictionless ramp that is inclined at an angle of 53.1
Homework Answers
a) normal force = gmcos(theta) = 9.8*0.221*cos(53.1) = 1.3004 N
b) force = 9.8*0.221*sin(53.1) = 1.732 N
normal force = mg cos theta
= 0.221 * 9.80 * cos53.1
= 1.3 N
part b)
F g = mg sin theta
= 0.221 * 9.8 * sin (53.1)
= 1.73 N
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