Question

To move a box you pull on the handle as indicated in the diagram shown below with a constant force F = (4.55i + 2.905)N. The mass of the box is m = 4.00 kg. what is the magnitude of the normal force acting on the box? Enter a number free body diagram and identify all the forces acting on the object? What is the net force in the vertical direction? N 下 Additional Materials

Answer 1

Given,

F = 4.55 i + 2.9 j ; m = 4 kg

The normal force will be:

N = mg - F sin(theta)

theta = tan^-1(2.9/4.55) = 32.51 deg

F = sqrt (4.55^2 + 2.9^2) = 5.39 N

N = 4 x 9.81 - 5.39 x sin32.51 = 36.34 N

Hence, N = 36.34 N