Question

4 (ms) The figure shows an approximate plot of force magnitude F versus time t during the collision of a 38 g Superball with a wall. The initial velocity of the ball is 50 m/s perpendicular to the wall, the ball rebounds dircctly back with approximately the same speed, also perpendicular to the wall. What is the magnitude the change in momentum of the ball? Submt Answer Tries 0/5 Remembering that the impulse can be found by taking the area between the F vs t curve and the zero line, which expression glves the impulse by the force on the ball? Correct: 1/2*Fmax*2 ms Fmax 2 ms 1/2* Fmax*2 ms Incorrect Fmax*6 ms Incorrect 1/2 Fmax*6 ms You are correct. Yaur receipt no. is 158-232 Previous Tries What is Fmax? Sui Anw Tries 0/5 (N)

Answer 1

(1) charpe in momentum Ap= mx (Vf - V;) B = 38x10 3 (50-1-50) = 3-8 kg m/s Awower (2) Impulse = area E x2 ms + Max Fr. Xams t Lxf x2ms my (3) 2x Fucy (2+4+2)+103 = 3.8 & max = 950 N Anson