Question

I'm using up the last of my questions, forgive me.

I need some help confirming if I got Problems 2, 3, and 4 correctly.

Problem 1: If Mr. Simpson weigh 741N on Earth where g = 10 m/s and 5320 N on the surface or another planet, what is the acceleration due to gravity on that planet? 74.8 m/s 2 Problem 2: According to the image shown: Considering the mass of the box 10 Kg and a force of 20 N applied by the man pulling the box: b) Calculate the acceleration of the box. Use a kinetic friction coefficient of 0.01. c) If the box is moved 5 m. what is the work done by the man on the box? 6) 0.0110 x 9.817.32-0.96= 16.34 1C.3410 a a1,634m/5 =Q.98N FLeriZantel Fco530 20x3 30° C) = 20 x 5 XCO530° Joules 3.205 -17.32N Problem 3: An initially at rest ball falls vertically from a height of 4.0 m experiences no air resistance as it falls. At what velocity will its gravitational potential energy (relative to the base level) be equal to its kinetic energy? 6,3m/s Problem 4: Objects shown in the figure collide and stick and move together after the collision. Find final velocity's objects. Takes positive direction from left to right. 4.14 m/s m-4 kg V10 m/s m 3 kg

Answer 1

de B JA Senso SACOSO Ang In urtia Nt f In U = mg Na mg-ffin fnet = Flaso-fr flood- UNI f Coso-uma tufli = 20 Cas30" - 0.01 X 10x 9.8 +0.01 X20X Ser 30 - 17.32 0.98 tou E 16.44 N Frutma 16:44=10x a a 1.644 mb- © W = F Cooxd POX B xs TW = 86.60 J Il you have Carrution in this

Problem 3 At 2m 4. E = potential bergy nigh: 2 vrh V: Vagh V- Sex 9.8x2 IV = 6.26 mb Problem @ Pi=PA mv, tm, V = (mitm) v. 3x8 + 48 (-10) = (3+4) V. 24-405 TV -16=7V JVE - .28 Mb

Comment for any further help.