Homework Answers
prior change:
P(2 defects) =(e-0.04*0.042)/2! =0.000769
after reducing lambda 50% to 0.02
P(2 defects) =(e-0.02*0.022)/2! =0.000196
Therefore change in the probability of finding exactly 2 defects from improvement =0.000769-0.000769
=0.000573
(or in % term =(0.000573/0.000769)*100 =74.49 %)
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