given that f(x)=x4-2x3-5x2+12x-5
Let us take x0=0,x1=1,x2=2
f(x0)=(0)4-2(0)3-5(0)2+12(0)-5=-5
f(x1)=(1)4-2(1)3-5(1)2+12(1)-5=1-2-5+12-5=1
f(x2)=(2)4-2(2)3-5(2)2+12(2)-5=16-16-20+24-5=-1
Question 2: 60 Marks The function fx)-x-2x3-5x2+12x -5 as four distinct roots, we want to determine...
71 60. 321z+ 61.-2x3 + 5x2-3x+9=0 62. _x3 + 8x-12-0 Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in finding all real and imaginary root 0 to each equation. 一63. x3-4x2-7x+10=0 一64. x3 + 9x2 + 26x + 24 = 0 -65. r3-10x-3=0 66. 2x3-7x2 160 一68. x4-4x3 + 7x2-16x + 12 = 0 69, 6' + 25x2-24x + 5 = 0 70·6x3-11x2-46x-24 0 --71. x4 + 2x3-3x2-4x+4-0 72, x5 + 3x3...