Question

32. Multiply or find the special product (x-3) a. - 9x +27x+27 b. x-9x®-27x-27 c. X-9x +27x-27 d. x +9x +27x+27 e. +9x°-27x+2
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Answer #1

32. (x - 3)3

= (x - 3)(x - 3)2

= (x - 3)(x2 - 6x + 9)

= x3 - 6x2 + 9x - 3x2 + 18x - 27

= x3 - 9x2 + 27x - 27

33. (3 + \sqrt{x})(3 - \sqrt{x})

= (3)2 - (\sqrt{x})2 [Since a2 - b2 = (a + b)(a - b)]

= 9 - x

34. x2 - 16

= x2 - (4)2

= (x + 4)(x - 4) [Since a2 - b2 = (a + b)(a - b)]

35. x2 - 16x + 64

= x2 - 2(8)x + (8)2

= (x - 8)2 [Since (a - b)2 = a2 - 2ab + b2]

36. x4 - 4x3

= x3 (x - 4)

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32. Multiply or find the special product (x-3) a. - 9x +27x+27 b. x-9x®-27x-27 c. X-9x...
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