What is the correct formula/ procedure for determining the confidence interval
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The sample size, 
Sample standard deviation, 
Sample mean, 
Determine the degrees of ferndom using the following formula,
From the 
distribution tables, the critical value at 5% level of the significance about two tailed test is
.
Determine the 95% confidence interval for the mean bill of all lunch orders using the following formula,
Therefore, the 95% confidence interval for the mean bill of all lunch orders is lies between 
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What is the correct formula/ procedure for determining the confidence interval
A random sample of 29 lunch orders at Noodles & Company showed a mean bill of...
A random sample of 29 lunch orders at Noodles & Company showed a mean bill of $9.60 with a standard deviation of $5.73. Find the 95 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) to The 95% confidence interval is from
Confidence Interval
A random sample of 41 car owners was taken to try to determine the mean length of car ownership for all owners. The sample resulted in a mean of 3.98 years and a standard deviation of 1.5 years. The data is normally distributed. Form a 95% confidence interval for the mean length of car ownership. The confidence interval would be 3.98 what margin of error?
Itl 5 LTE Confidence Interval for the P... DOCX -16 KB Close Confidence Interval for the Populati...
statistics
itl 5 LTE Confidence Interval for the P... DOCX -16 KB Close Confidence Interval for the Population Mean l. Determine the critical values for 80%, 90%, 95%, and 99%; 2. Construct 80%, 90%, 95%, and 99% confidence interval for the population mean given that the standard deviation of the population is 900 and the sample mean is 425 and the sample consist of 100 points of data 3. Find the T interval for the following: Construct 80% 90%. 95%,...
Use th e confidence level and sample data to find a confidence interval for estimating the...
Use th e confidence level and sample data to find a confidence interval for estimating the population 15) 42 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 26.7 pounds and a standard deviation of 2.9 pounds. What is the 95 percent confidence interval for the true mean weight, μ, of all packages received by the parcel service? 25.8 < μ < 27.6 b, 26.0< μ< 27.4 c. 25.7< μ< 27.7...
Use the given degree of confidence and sample data to find a confidence interval for the...
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation . Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation. 21) A sociologist develops a test to measure attitudes about public transportation, and 27 randomly selected subjects are given the test. Their mean score is 76.2 and their standard deviation is 21.4. Construct the 95%...
Use the given degree of confidence and sample data to find a confidence interval for the...
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a nomn to the same number of decimal places as the sample standard deviation. al distribution. Round the confidence interval limits 7) The mean replacement time for a random sample of 20 washing machines is 10.9 years and the standard deviation is 2.7 years. Construct a 99% confidence interval for the standard deviation, o, of...
Using techniques from Section 8.2, we can find a confidence interval for μd. Consider a random...
Using techniques from Section 8.2, we can find a confidence interval for μd. Consider a random sample of n matched data pairs A, B. Let d = B − A be a random variable representing the difference between the values in a matched data pair. Compute the sample mean d of the differences and the sample standard deviation sd. If d has a normal distribution or is mound-shaped, or if n ≥ 30, then a confidence interval for μd is...
Use the given degree of confidence and sample data to find a confidence interval for the...
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal pl aces as the sample standard deviation. 21) A sociologist develops a test to measure attitudes about public transportation, and 27 21) randomly selected subjects are given the test. Their mean scoreis 76.2 and their standard deviation is 21.4. Construct the...
Please find the confidence interval for a, b, & c. A random sample of 91 observations...
Please find the confidence interval for a, b, & c.
A random sample of 91 observations produced a mean x a. Find a 95% confidence interval for μ. b. Find a 90% confidence interval for μ. C. Find a 99% confidence interval for μ. 25.7 and a standard deviation s- 2.4. a. The 95% confidence interval is (Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.)
I need the completed and correct answer asap. thank you A 95% confidence interval for a...
I need the completed and correct answer asap. thank
you
A 95% confidence interval for a population mean is from 101 to 104. What can we conclude from this? For 95% of all possible samples from this population, the confidence interval calculation will produce an interval contaming the population mean, so, based on this sample, we believe the population mean is between 101 and 104 The population mean is between 101 and 104 95% of all possible samples from this...
A random sample of 29 lunch orders at Noodles & Company showed a mean bill of $9.60 with a standard deviation of $5.73. Find the 95 percent confidence interval for the mean bill of all lunch orders. (Round your answers to 4 decimal places.) to The 95% confidence interval is from
A random sample of 41 car owners was taken to try to determine the mean length of car ownership for all owners. The sample resulted in a mean of 3.98 years and a standard deviation of 1.5 years. The data is normally distributed. Form a 95% confidence interval for the mean length of car ownership. The confidence interval would be 3.98 what margin of error?
statistics
itl 5 LTE Confidence Interval for the P... DOCX -16 KB Close Confidence Interval for the Population Mean l. Determine the critical values for 80%, 90%, 95%, and 99%; 2. Construct 80%, 90%, 95%, and 99% confidence interval for the population mean given that the standard deviation of the population is 900 and the sample mean is 425 and the sample consist of 100 points of data 3. Find the T interval for the following: Construct 80% 90%. 95%,...
Use th e confidence level and sample data to find a confidence interval for estimating the population 15) 42 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 26.7 pounds and a standard deviation of 2.9 pounds. What is the 95 percent confidence interval for the true mean weight, μ, of all packages received by the parcel service? 25.8 < μ < 27.6 b, 26.0< μ< 27.4 c. 25.7< μ< 27.7...
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a nomn to the same number of decimal places as the sample standard deviation. al distribution. Round the confidence interval limits 7) The mean replacement time for a random sample of 20 washing machines is 10.9 years and the standard deviation is 2.7 years. Construct a 99% confidence interval for the standard deviation, o, of...
Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal pl aces as the sample standard deviation. 21) A sociologist develops a test to measure attitudes about public transportation, and 27 21) randomly selected subjects are given the test. Their mean scoreis 76.2 and their standard deviation is 21.4. Construct the...
Please find the confidence interval for a, b, & c.
A random sample of 91 observations produced a mean x a. Find a 95% confidence interval for μ. b. Find a 90% confidence interval for μ. C. Find a 99% confidence interval for μ. 25.7 and a standard deviation s- 2.4. a. The 95% confidence interval is (Use integers or decimals for any numbers in the expression. Round to two decimal places as needed.)
I need the completed and correct answer asap. thank
you
A 95% confidence interval for a population mean is from 101 to 104. What can we conclude from this? For 95% of all possible samples from this population, the confidence interval calculation will produce an interval contaming the population mean, so, based on this sample, we believe the population mean is between 101 and 104 The population mean is between 101 and 104 95% of all possible samples from this...
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