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A spring hangs vertically from a fixed support. A mass is then attached to the lower...

A spring hangs vertically from a fixed support. A mass is then attached to the lower end of the spring. When this system undergoes simple harmonic motion, it has a period of 0.36 s. By how much is the spring stretched from its initial length when the mass and spring are hanging motionless?

m=?

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Answer #1

Sqrt(m/k) = 0.36/(2 pi)

Sqrt(m/k) = 0.057

Squaring both sides

m/k = 0.00328 ...... (1)

Force, F = mg = kx

x = mg/k

x = 9.8 x 0.00328 = 0.032 m

Comment in case any doubt please rate my answer....

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