A spring hangs vertically from a fixed support. A mass is then attached to the lower...
A spring hangs vertically from a fixed support. A mass is then
attached to the lower end of the spring. When this system undergoes
simple harmonic motion, it has a period of 0.36 s. By how much is
the spring stretched from its initial length when the mass and
spring are hanging motionless?
m=?
Homework Answers
Sqrt(m/k) = 0.36/(2 pi)
Sqrt(m/k) = 0.057
Squaring both sides
m/k = 0.00328 ...... (1)
Force, F = mg = kx
x = mg/k
x = 9.8 x 0.00328 = 0.032 m
Comment in case any doubt please rate my answer....
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