Question

The confidence interval for ml-m2(5.34,685) having a 95% of confiability, then: a.ml-m2 b. mi > m2 c. mi <m2 d ant be determinated 2) The confidence interval for sl/s2 - (0.87,103) having a 95% of confiability, then: a.si - 52 b. sis2 c. 52 d. Cant be determinated 3) The interval confidence for sl 2/522-(3.48, 5.25) with a 95% of confiability, then: a. sl -1.865 y 52 -2.291 b. si 2-3.48 y 22 -5.25 G. SI52 dant be determinated 4) The confidence interval for ml-m2-(-3.35,-2.45) having a 95% of confidence, then: a. Can concluded that ml-m2 b. Can concluded thatm'm2 es false c. Can concluded thatm >m2. d. Can concluded that mi-m2--3 5) Process A involves adding an ingredient to a misture. Process B involves extracting an ingredient from that same mixture How much is SAB? a. SASB b. SA-SB C. SA 2+SB2 d. VSA 2-SB 6. If the interval confidence for sl 2.522-(-0.45, 1.05) with a 95% of confiability, the: a. si 2522 b. si 21522 c. sl 2-522-0 d Makes no sense 8) A process follows a normal distribution with Barlett fit mean is given by the following equation B-sinh-i de -xdx 43 de xdx 43 ) 187,454 4 Another process follows a nonparametric distribution with Fibonacci adatment. Its mean is given by the following: m o sh-1(x) dx 43 The interval confidence mB-MF (-0.02. 2.48) fa al 99% of confiability. I can concluded that amBmF b. The mean of the adjustment Barlet and the adjustment Fibonacci for the range of X-3.) are the same when a 99% of confiability c. (sinh 1 ( e xdx 43 ) p 444- trị cosh-1 (x) dx 43 d. All of the above 9) The limits of specification of a process X<2.5. Which stadistic should I use for the interval confidence of the media a. Za b.m c. 2 d. Za

Answer 1

1.

Option b : m1 > m2

( since the the lower and upper limit of confidence interval are positive. The confidence interval do not contain zero hence m1 is not equal to m2 and the confidecne interval has no negative value hence m1 is not less than m2)

2.

Option d : can't be determined

( as the lower limit is less than 1 which tells that S1 maybe less than S2, but upper limit is greater than 1 which tells that S1 Amy be greater than S2 and confidecne interval also contains 1,hence S1 may be equal to 1 also.)

3.

Option d : can't be determined

( as the confidence interval is given for s12/s22, the lower limit is 3.48 and this value can be obtained by many values of s12 and s22. Hence it doesn't specify a single value of s12 or s22, similarly upper limit does not specify a single value of s12 or s22)

4.

Option d : m1 - m2 = - 3

(as the confidence interval does not include zero hence m1 is not equal to m2, interval does not have positive value hence m1 is not greater than m2 and the midpoint of interval is around - 3, hence m1 - m2 = - 3 can be concluded.)

6.

Option a : s12 = s22

( since the confidence interval contains zero value in it)