Let X be the number of fluorescent light that has a useful life of atleast 800 hours is 0.9
P(success) p = 0.9 ,q =1-p =1-0.9= 0.1
a)probablity that exactly 18 out of 20 bulbs will have a useful life of atleast 800 hrs is:
P( 18 will have useful life) =P(X=18) = 0.285
b)probablity that less than 2 out of 20 bulbs will have a useful life of atleast 800 hrs is:
P( less than 2 out of 20) =P(X<=2)= 0.999
c)
P(at least 3 will not have a useful life) = P(at most 17 will have useful life) = 0.99
4.(25 pts) The probability that a fluorescent light has a useful life of at a. Find...
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