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How long must a 0.64-mm-diameter aluminum wire be to have a 0.54 A current when connected to the terminals of a 1.5 V flashli

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Answer #1

A)

Resistance, R = V/I

R = 1.5/0.54 = 2.78 ohm

Resistance, R = pL/(pi/4) d^2

Length, L = (pi x 0.00064^2 x 2.78)/(4 x 2.82 x 10^-8)

L = 31.69 m

B)

R' = 2.78/2 = 1.39 ohm

Current, I = 1.5/1.39 = 1.08 A

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