let the acceleration of the system be a m/s^2
writing the force equation for both the blocks we have
5g - T = 5a --------(1)
T - 5gsin37 - u*5*g*cos 37 = 5a ----------(2)
u = 0.25
adding both equation we have
3g = 10a
a = 3*9.8/10 = 2.94 m/s^2
T = 5(g - a) = 5*(9.8 - 2.94) = 34.3 N
c) v^2 = u^2 + 2aS
v^2 = 0 + 2*2.94*1 = 5.88
KE = 0.5*m*v^2 = 0.5*5*5.88 = 14.7 J