Since the kinetic energies are the same
Therefore
...(1)
The ratio of de Broglie wavelength is
Using the relation (1) one obtains
Chapter 29, Problem 53 An electron and a proton have the same kinetic energy and are...
A proton and an electron are both accelerated to the same final kinetic energy. If λ p is the de Broglie wavelength of the proton and λ e is the de Broglie wavelength of the electron, then λ p < λ e. λ p > λ e. λ p = λ e.
Electrons in an electron microscope have a kinetic energy of 6.01 105 eV. (a) Find the de Broglie wavelength of the electrons. (b) Find the ratio of this wavelength to the wavelength of light at the middle of the visible spectrum (550 nm). (c) How many times greater magnification is theoretically possible with this microscope than with a light microscope?
If an electron, a soccer ball, and a proton all have the same momentum, which has the shortest de Broglie wavelength? soccer ball electron proton all have the same wavelength It depends on the energy of the electron. What is de Broglie wavelength of a proton traveling with a speed of 3.25 × 106 m/s if its mass is mp = 1.67 × 10–27 kg A. 1.22 * 10-13 m B. 0.763 x 106 m C. 3.41 x 10-9 m...
8. Find the kinetic energy of an electron whose de Broglie wave- length is the same as that of a 100-keV x-ray. 9. Green light has a wavelength of about 550 nm Through what
A nonrelativistic electron has a larger de Broglie wavelength than a nonrelativistic proton. Which one of the following statements about these particles must be accurate? A) The proton has more momentum than the electron B) Both particles have the same kinetic energy. C) The proton has more kinetic energy than the electron. D) The electron has more kinetic energy than the proton. E) The electron has more momentum than the proton. Answer is A. Pleas explain step by step how...
How fast does a proton have to be moving in order to have the same de Broglie wavelength as an electron that is moving at 5.20 × 106 m/s?
For a free electron with 100 keV kinetic energy, calculate the: a) electron speed b) electron momentum c) de Broglie wavelength of the electron
An electron starting from rest acquires 1.34 keV of kinetic energy in moving from point A to point B. 1) How much kinetic energy would a proton acquire, starting from rest at B and moving to point A? 2) Determine the ratio of their speeds at the end of their respective trajectories.
Consider electrons of kinetic energy 5.29 eV and 529 keV. For each electron, find the de Broglie wavelength (in nm), particle speed (in m/s), phase velocity (speed, in m/s), and group velocity (speed, in m/s). nm 5.29 eV electron de Broglie wavelength particle speed phase velocity group velocity m/s m/s m/s 529 keV electron nm de Broglie wavelength particle speed phase velocity group velocity m/s m/s m/s
I need help with the problem below: Chapter 29, Problem 26 What is (a) the wavelength of a 3.90-eV photon and (b) the de Broglie wavelength of a 3.90-eV electron? (a) Number (b) Number Units Units