Question

7.1 When there are two traveling waves of the same wavelength and frequency (hence the same velocity) in phase: fA (x, t) A sin(kx- ot) fs (x, t) B sin(kx ot) then its clear that the actual wave you observe is fa B fA (x, t)+ fs (x, t (A B) sin(kx-ot) due to superposition principle. Namely, you observe the same wave form, except now the amplitude is A+ B. Now consider there are two waves of the same wavelength and frequency (hence the same velocity), but are not in phase: fA(x, t A sin(kx-ot) fa (x, t)-B sin(kx- t + ?) where p is a phase constant. Follow the steps prescribed below and derive the actually observed wave.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A10 .ma = ASinCkv-toy) +6sincus.not+4) at t-o and D Jetf

Add a comment
Know the answer?
Add Answer to:
7.1 When there are two traveling waves of the same wavelength and frequency (hence the same...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT