Question

Problem 20.71 A long, straight wire carries a current of 10.0 A, as shown in the figure 5.00 cm A ←-7.00 cm 10.0A Part A Use the law of Blot and Savart to find the direction of the magnetic field at point P due to the 2.20 mm segment A ANSWER The field is directed into the page. The field is directed out of the page. The field is directed to the right. The field is directed to the left. Part B Use the law of Biot and Savart to find the magnitude of the magnetic field at point P due to the 2.20 mm segment A ANSWER: BA = Use the law of Biot and Savart to find the direction of the magnetic field at point P due to the 2.20 mm segment C. ANSWER:

Answer 1

Here ,

Biot savart's law is

B = u0*I*dl X r/(4pi*r^3)

part A)

the direction of field due to sagment A is Out of the page

the field is out of the page ,

part B )

for point A , r = sqrt(7^2 + 5^2)

r = 8.60 cm = 0.086 m

field at A = u0 * ( 10 * 2.2 *10^-3 * 0.086)/(4pi* 0.086^3)

BA = 2.98 *10^-6 T

the magnetic field due to sagment A is 2.98 *10^-6 T

part C )

for sagment C ,

r = 0.05 m

the direction of field due to sagment C is Out of the page

the field is out of the page ,

part D)


field at D = u0 * ( 10 * 2.2 *10^-3 * 0.05)/(4pi* 0.05^3)

BD = 8.802 *10^-6 T

the magnetic field due to sagment A is 8.802 *10^-6 T