Question

Write in c and in the simplest form (beginner)

Write a program pointers with multi-dimensional integer array [2] [4]. Use data set {#,88,89,90},{?,65,66,67}.

Now the input characters would be converted to ASCII decimal value and put into the first cell of the row’s array, and so on.

When getting the values out of the array, convert the decimal value to equivalent ASCII character.

Print the address of the first array followed by the four decimal values, followed by the four characters of their ASCII decimal value. Do the same for the second row. All values to be place and gotten be pointer.  

<END

Answer 1

1 #include <stdio.h> 3 int main(void) { clang version 7.0.0-3-ubuntu. 18.04.1 (tags/RELE } clang-7 -pthread -LM -o main main.c } ./main First row address: Ox7ffc85da6060 Data: # X Y Z Second row address: 0x7ffc85da6070 Data: ? ABC int data[2][4] = { {'#', 88, 89, 90}, {'?', 65, 66, 67} }; printf("First row address: %p \nData: ", &data[0]); for(int i=0; i<4; i++) { printf("%c ", data[0][i]); printf("\n"); printf("Second row address: %p \nData: ", &data[1]); for(int i=0; i<4; i++) { printf("%c ", data[1][i]); printf("\n"); return 0;

#include <stdio.h>

int main(void) {

        int data[2][4] = {
                {'#', 88, 89, 90},
                {'?', 65, 66, 67}
        };

        printf("First row address: %p \nData: ", &data[0]);
        for(int i=0; i<4; i++) {
                printf("%c ", data[0][i]);
        }
        printf("\n");

        printf("Second row address: %p \nData: ", &data[1]);
        for(int i=0; i<4; i++) {
                printf("%c ", data[1][i]);
        }
        printf("\n");

        return 0;
}

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