ZnCO3 (s) <—> Zn2+(aq) + CO32- (aq) k1 = 1.5*10^-10
HCO3-(aq) <—> CO32- (aq) + H+(aq) k2 = 5.6*10^-11
reverse the 2nd reaction:
ZnCO3 (s) <—> Zn2+(aq) + CO32- (aq) k1 = 1.5*10^-10
CO32- (aq) + H+(aq) <—>HCO3-(aq) k3 = 1/k2
k3= 1/(5.6*10^-11) = 1.79*10^10
now add both reaction:
ZnCO3 (s) + H+(aq) <—> Zn2+(aq) +HCO3-(aq)
this is the required reaction
kc = k1*k3
= (1.5*10^-10)*(1.79*10^10)
= 2.7
Answer: c
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