Question

INUIR 2 MAT 147 S 20 - MAT 147, section 71, Spring 2020 WebAssign x2 reduce the overall risk of an investment portfolio? Let

Ey 107 3520 19 1369 78% 176 28 (0) Use the results of part (a) to compute the sample mean variance, and standard deviation fo

Mic mean for u 8.9 Lower Limit Upper Limit Use the intervals to compare the two funds 75% of the returns for the balanced fun

Homework 2 MAT 147 S 20 - MAT 147, section 71, Spring 2020 Wasign Need Help? Read it ir two events A and B are independent an

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Answer #1

Note- The sum of square of y is wrongly calculated as 3521 in the given calculation over the image of the problem. The correct sum of squares of y is calculated and the whole problem is solved with corrected value as follows.

(a)

Στ = 116    x2 = 5456

Σy = 107    Συ? = 3221

(b)

- 10/ r = 11.6    Ο – Συ= 10.7

6 = Σ( – 1)2 = 456.71    2 = 0 Συ - ) = 230.68

Sy = 456.71 = 21.37Sy = V230.68 = 15.19

(c)

We know, Chebyshev's inequality is given by

P(|X – Hl> ko) <

= P(X -H 5ko) 21 -

We estimate population mean \mu by corresponding sample mean and population standard deviation \sigma by sample standard deviation.

To obtain 75% interval we have

12 = 0.25 k= 2

So, 75% Chebyshev interval around mean is given by (μ – 2σ, μ+ 2ο) .

x y
Lower limit -31.14 -19.68
Upper limit 54.34   41.08

Range is 4\sigma in both cases. So, it is directly depending upon value of standard deviation. As Sy <S we can conclude that 75% of the returns for the balanced fund fall within a narrower range than those of the stock fund.

(d)

Coefficient of variation is defined as

CV

We use sample standard deviation in place of population standard deviation and sample mean in place of population mean.

CV = 21.37 -* 100% = 184.22% 11.6

CV 15.19 10.7 * 100% = 141.96%

Since CV > CV we can conclude that for each unit of return, the balanced fund has lower risk.

We know CV denotes coefficient of variation i.e. the average amount of variation. So, a smaller CV is better because it indicates lower risk per unit of expected return.

If two events A and B are independent, then P(A|B) = P(A) = 0.20 [As occurrence of A is independent of occurrence of B]

During computation of standard deviation, use of sample data or data comprising the entire population matters and the cause is as follows.

Yes. The formula for s is divided by n-1, while the formula for \sigma is divided by N.

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