According to HOMEWORKLIB RULES we have to answer only first one problem
stoichiometry of balance reaction, indicates the relationship between reactant and products of any chemical reaction.
a.
NCl3 + 3 H2O ----- > NH3 + 3 HOCl
b.
given that wate r= 275 g
number o fmole s= amount in g / molar mass
= 275 g/ 18.02 g/ mole
= 15.3moles H2O
15.3 Mole H2O * 1 mole NH3 /3 mole H2O
= 5.1 mole NH3
c.
14.8 g NH3
Number of mole s= 14.8 g/ 17.031 g/mol
=0.869 mole NH3
NCl3 + 3 H2O ----- > NH3 + 3 HOCl
0.869 mole NH3 *1 mole NCl3 /1 mole NH3
= 0.869 mole NCl3
Amount in g = number of mole * molar mass
= 0.869 mole NCl3*120.365 g/mol
= 104.6 g NCl3
d.
3. 2 mole H2O
2.0 mole NCl3
NCl3 + 3 H2O ----- > NH3 + 3 HOCl
2.0 mole NCl3 *3 mole H2O /1 mole NCl3
= 6.0 mole H2O
3. 2 mole H2O *1 mole NCl3 / 3 mole H2O
= 1.07 Mole NCl3
The limiting agent has following properties:
Thus H2O is a limiting agent
e.
excess reagent is NCl3 which is = 2.0 mole NCl3 -1.07 Mole NCl3
= 0.93 Mole NCl3
Amount in g = number of mole * molar mass
= 0.93 mole NCl3*120.365 g/mol
= 111.94 g NCl3
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