wi = 2600 rev/min = 3600*2pi/60 rad/s = 376.8 rad/s
wf = 0
θ = 50 turns = 50*2pi = 100pi = 314 radians
From 3rd equation of motion
wf^2 = wi^2 + 2αθ
0 = 376.8^2 + 2α*314
=> α = -226.08 rad/s^2
Hence the magntiude of angular acceleration is 226.08 rad/s^2
Please do FULL problem A centrifuge in a medical laboratory rotates at a rotational speed of...
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