Question

(1 point) A 100 μF capacitor is connected to a source that operates at 70 Hz with a peak potential difference of 16 V (so an amplitude). Find: a) the peak current; 0.70 A b) the rms current; -0.610 A c) the current when the potential difference has its peak value; 0 A d) the current when the potential difference has one-half the (positive) peak value (there are two answers, list them in increasing order); -0.610 A 0.610 A Hint, there are two possible angles within 0-2 pi when you try to find time by using the arcsin function. e) the instantaneous power delivered by the source at 6 ms. This will be the product of i and V at this point in time. Remember to switch your calculator to radian mode!

Answer 1

a) capacitive reactance, Xc 257C » Xc = & = 22.736 2 anx 70 x 1ooxiol Peak current - Peak voltage 36 = 0.7A 6) kes current = = 0.5A because there is a c) corrents will be reso phase difference of Tz between merent and voltage. d) Exam Vevo sincwt) given, v= Vol2 vosin (wt) = No/ + sin(w) - se, with or * t - over t o wit= ST Some t: ST 6x22x70 => t = Gx anx70 3 - - 1.19X10 t = S or 5.95 x 10 t=

current, I To coswt) do cos cante) I dot cos (25 X 70 X 1019x103) = 0.606 A and I – 0.7 Cos (22 x 10 x 5.958103 = -0.606 A Ammer – – 0.606A; 8. 606 A e) at ome – Conos, v=16 sin (25 x 70 x 6x103) – 7.708 v I= 0.7 cos (2*x 70 x 6x103). –– 00 613 A Instantaneous Power, Pavel = 7.708 *(-0.613) -4.725 W