Solution :
Given that ,
mean =
= 100
standard deviation =
= 15
P(x >89 ) = 1 - P(x<89 )
= 1 - P[(x -)
/
< (89 -100) /15 ]
= 1 - P(z <-0.73 )
Using z table
= 1 - 0.2327
= 0.7673
area=0.7673
6.2.6-T Question Help Find the area of the shaded region. The graph to the right depicts...
find the area of the shaded region the graph to the right
depicts IQ scores of adults and those scores are normally
distributed with a mean of 100 and a standard deviation of 15 the
area of the shaded region is 85-125
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Please Help Me Anser Following A-D :)
A)
B)C)D)
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 125 The area of the shaded region is . (Round to four decimal places as needed.) Find the area of the...
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 70 115 The area of the shaded region is (Round to four decimal places as needed.)
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