1)
use:
pH = -log [H+]
2.581 = -log [H+]
[H+] = 2.624*10^-3 M
HA dissociates as:
HA -----> H+ + A-
0.414 0 0
0.414-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 2.624*10^-3*2.624*10^-3/(0.414-2.624*10^-3)
Ka = 1.674*10^-5
Answer: 1.67*10^-5
2)
use:
pH = -log [H+]
2.504 = -log [H+]
[H+] = 3.133*10^-3 M
HA dissociates as:
HA -----> H+ + A-
0.591 0 0
0.591-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 3.133*10^-3*3.133*10^-3/(0.591-3.133*10^-3)
Ka = 1.67*10^-5
Answer: 1.67*10^-5
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