Question

Question 2 1.0 cm Integration path Determine the value for the line integral of the magnetic field between points i and f. The current through the wire is 2.00 A and the distance between points i and fis 14.2 cm. 2.51x10-6 Tm 2.06x10-6 Tm O 3.77x10-6 Tm 1.26x10-6 Tm Question 3 451 An electron travels through a magnetic field with a strength of 4.10 T and is traveling at a speed of 8.96x107 m/s. What is the force on the electron as shown in the figure? 4.16x10-11 (Î + ) N 5.88x10-11 (j + k) N 5.88x10-11 (-; - k) N 4.16x10-11 (-) - k) N

Answer 1

Question 2 :

Since we have semicircle , Line integral of magnetic field is given as

Line integral of magnetic field = $\mu _{o}$ I

Line integral of magnetic field = (12.56 x 10^-7) (2)

Line integral of magnetic field = 2.51 x 10^-6 Tm

Question 3 :

In unit vector notation we have

$\underset{B}{\rightarrow}$ = 4.10 i + 0 j + 0 k

$\underset{v}{\rightarrow}$ = 0 i - (8.96 x 10⁷) j + (8.96 x 10⁷) k

q = charge on electron = - 1.6 x 10^-19 C

Force on electron is given as

$\underset{F}{\rightarrow}$ = q ($\underset{v}{\rightarrow}$x $\underset{B}{\rightarrow}$ )

$\underset{F}{\rightarrow}$ = (- 1.6 x 10^-19) ((0 i - (8.96 x 10⁷) j + (8.96 x 10⁷) k) x (4.10 i + 0 j + 0 k))

$\underset{F}{\rightarrow}$ = (- 1.6 x 10^-19) (0 i + (3.67 x 10⁸) j + (3.67 x 10⁸) k)

$\underset{F}{\rightarrow}$ = 0 i - (5.88 x 10^-11) j - (5.88 x 10^-11) k

$\underset{F}{\rightarrow}$ = (5.88 x 10^-11) (- i - j )