Question

1.

(i) Select the reagent system you're going to get to start the synthesis of the alkyne hept-2-yne. Starting material is ethyne.

sodium hydroxide in water

sodium hydroxide in ethanol   

sodium hydroxide in ammonia

sodium ethoxide in water

sodium ethoxide in ethanol

sodium ethoxide in ammonia

sodium amide in water

sodium amide in ethanol

sodium amide in ammonia

(ii) Name the alkyne below.

CH3CH2CH2CH2CECH

(iii) You need to finish the synthesis. Select the reagent you need. (refer to image below)

Options:

sodium hydroxide in water

sodium hydroxide in ethanol  

sodium hydroxide in ammonia

sodium ethoxide in water

sodium ethoxide in ethanol

sodium ethoxide in ammonia

sodium amide in water

sodium amide in ethanol

sodium amide in ammonia

(iv) Draw the resulting alkylating agent you need. Please use an alkyl bromide for the alkylating agent.

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Answer #1

1.

I) sodium amide in ammonia

II) name of the given alkyne is:- Hexyne

III) sodium amide in ammonia

IV) we need n-butyl bromide

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