Question

Chapter 26, Problem 051 Your answer is partially correct. Try again. Wire C and wire D are made from different materials and have length Lc = L - 2.9 m. The resistivity and diameter of wire Care 5.2 x 10 Rim and 1.04 mm, and those of wire D are 1.9 x 100 m and 0.66 mm. The wires are joined as shown in the figure and a current of 3.0 A is set up in them. What is the electric potential difference between (a) points 1 and 2 and (b) points 2 and 3? What is the rate at which energy is dissipated between (c) points 1 and 2 and (d) points 2 and 3? (a) Number Unitsſtv (b) Number (c) Number Units Units w the tolerance is +/-2% (d) Number Units T W SHOW HINT GO TUTORIAL

Answer 1

Answer! Given that Le LD: 8.9m Pi= 5.28106 rom P2 = 19*166 Rom dis 104mme louxcom de = 0.66 mm = 0.66X163 m I - BA forom į pornt's @ Re=fi 2 [2 rc = do] A=nra poco, & - (5.92106) Po is quibuy- ARC= 17.75 Uca IRC = (3) (17.75) = 53.25 ..Vc = 53.250] from ò points ① & ② RD / LO A= Tro? (19x109) 7 (0.33x16334 (RP = 16.18 os Vos PRO = 3) (16.1) Evo= 48.80 [Rode 7 2.9

& The at point e Energy dissipated Pe=I2Rc (3)e (17175)2 f. Pc=159.750 a The Energy dissipated at points PO = I2Ro = (3)² (161) (F.PO = 14190)
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