Question

A solid disk (I=1/2mr2)of mass 0.75kg is initially at rest at the top of an incline...

A solid disk (I=1/2mr2)of mass 0.75kg is initially at rest at the top of an incline of height h=2m.

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19)  If instead a solid sphere (I=2/5mr2)was allowed to roll down the same incline at the bottom its velocity would be

the same as the solid disk

less than the solid disk

greater than the solid disk

Now assume A=(3 m, 4 m) and B=(5 m, -3 m), where the first number is the x-component of the vector, and the second number is the y-component of the vector.

9)  What is the magnitude of vector A?

7 m

4 m

(8 m, 1 m)

5 m

(3 m, 4 m)

10)  What is A + B?

(8 m, 1 m)

7 m

(3 m, 1 m)

10.83 m

5.83 m

(7 m, 2 m)

0 0
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Answer #1

19. Note that for rolling objects in an incline, those with LESSER moments of inertia have GREATER VELOCITIES at the bottom of the incline.

Thus, the velocity will be GREATER THAN THE SOLID DISK. [OPTION C, ANSWER]

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