LRFD solution:
Step 1:
Wu=1.2(D.L)+1.6(L.L)
Wu=1.2(1)+1.6(2)
Wu=4.4 kips/ft
M=WuL2/8
Mu=4.4x24x24/8
Mu=316.8 ft-kips
Step 2:
Zx=Mu/(0.9Fy)
Zx=316.8x12/(0.9x50)
Zx=85 in3 is the required section modulus
Check with W16X50 and consider for self weight also
Self weight=0.05 ft/kips
Wu=1.2(1.05)+1.6(2)
Wu=4.46
Mu=4.46x24x24/8
Mu=321.12 ft-kips
Zx=321.12x12/(0.9x50)
Zx=85.6 in3
Provided is 92 in3
Step 3:
Finding the minimum radius of gyration:
Iy=37.2 in4
A=14.7 in2
ry=(Iy/A)0.5
ry=(37.2/14.7)0.5
ry=1.59 in
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