Question

1. A 45kg block is being pulled at a 25 degree angle on a surface by a force F. Assume that the static friction (μstatic) of the surface is 0.1 and the kinetic friction (μkinetic) is 0.03. Draw a free body diagram showing all forces acting on the block, and determine the minimum force F to get the block moving. What is the magnitude of the blocks acceleration once it starts to move if the force is maintained?

64G, А

Answer 1

H N arsin 659) 125 45kg cas(250) m = 45kg - Wang - Wang . Miminum force at which block is just about to nove but Net force is zero. Son Fret = F cas (250) - F o f cos250)- us N F cos (250) – us[W-F sim@50)] F cos(250) + Mg F sin (250) = ush F = us W cas 250) + us sin 659) F: 0.1 * 45kg *9.8 m/s2 cos (259) + 0.1 sin 259) TE= 46.49 N K Minimum force. Now block starts moving a So Mct force is Fret = Fos(25) f ma = F cas @56) -uk W-F sim50)] ma - (46.49 n) cos&56)- 0.03[45*9.8 - 46.49 sinks a - 29.49N29.49N- la = 0.65 m/s2) Please LIKE m 45kg