A 4 kg stone is whirled at a constant speed in a vertical circle of radius...
A 4 kg stone is whirled at a constant speed in a vertical circle of radius 1 m. At the bottom of the circle the tension is 2mg. The speed of the stone is _____ m/s?
Homework Answers
at bottom
T = mv^2/r + mg
2mg = mv^2/r + mg
2g = v^2/r + g
v^2/r = g
v = sqrt(rg)
v = 3.13 m/s
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