Question

The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 5.4 cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin.

-5.0 με +1.0 με -1.0 μ. +6.0 με (b)

Answer 1

EW The electric field exerted by the north charge is given by, Ex = atom (lon), That by the charge on the west is given by: Ev = ato Chan That by the est charge is given by, EE =- 1 47100 (19E r2 Then the total electric field at the origin will be the vector sum of the above electric fields. We are given : 9N = -54C,qw = 2C, E = -34C, r = 5.4cm

Then the total electric field will be: Ē = Ep + Ew + EF Ē = ((9w+ | 98 |)i+| 90 |j) le, 476219 Substituting the values: Ē = (1.54î + 1.549) x 10N/C We can follow the same steps as before except there is an extra charge at the southern point, Es = a (9),

and Ev = date (9); Given, ON = 1uC,qw = 4C, E = -14C,qs = 6C The total electric field at the origin is: E = -2((9w+ | qe )i + (45 – 9x)j) 476072 Substituting the values: Ē = (1.54ì + 1.54ņ) x 107N/C