p hat = X/n; where X is the number of spins that landed on Bankrupt and n is the total spins
p-hat = 25/40 = 0.625
p-hat in lieu of p. sigma-p-hat = p(1-p)/n)^.5 = (0.62 * 0.38/40)^.5 = 0.077
The z score of 99% confidence interval is 2.58
therefore, 99% confidence interval for p is:
(0.62 - 2.58*0.077, 0.62 + 2.58*0.077) = (0.42, 0.82)
WHEEL! OF! STATISTICAL INFERENCE The wheel from the Wheel of Fortune is pictured below. There are...
WHEEL! OF! STATISTICAL INFERENCE The wheel from the Wheel of Fortune is pictured below. There are many who say that the wheel must be fixed, because contestants land on backrupt too often. But how often is tooten? Complete the steps listed below to do an analysis of the wheel. Is the game fair? Let's find out! S $S 0 S ason Part I: Confidence Interval Watch 4 ul episodes of Wheel of Fortune. Record each spin as either Bankrupt or...
WHEEL! OF! STATISTICAL INFERENCE The wheel from the Wheel of Fortune is pictured below. There are many who say that the wheel must be fixed, because contestants land on backrupt too often. But how often is tooten? Complete the steps listed below to do an analysis of the wheel. Is the game fair? Let's find out! S $S S aso Part I: Confidence Interval Watch 4 ul episodes of Wheel of Fortune. Record each spin as either Bankrupt or "Not...
Entered Answer Preview 0.0625 0.0625 The answer above is NOT correct. (1 point) A wheel of fortune is pictured below. On any given spin, the probability of each wedge is proportional to its relative size in the wheel. The number in each wedge indicates its point value. Spin the wheel three times and sum the numbers. What is the chance of getting (exactly) 1 point total?0.0625 Entered Answer Preview 0.0625 0.0625 The answer above is NOT correct. (1 point) A...