Question

A)What is the molarity of a solution created with 34.4 g of C₆H₁₂O₆dissolved in 482 g of water to make 555 mL of solution?

B)What is the molality of a solution created with 36.4 g of C₆H₁₂O₆dissolved in 482 g of water to make 500. mL of solution?

C)A person is considered medically to have lead poisoning if they have a concentration of greater than 5 μg (micrograms) of lead per deciliter of blood. What is the concentration in parts per billion (ppb)? Assume 1 mL of blood weighs 1 g.

Answer 1

Weight of glucose (C_6 H_12 O_6) w = 34.49 rightarrow M.wt of glucose mwt = 180.155 g/mole rightarrow volume of solution v = 555 ml molarity = wl/m wt times 1000/v_ml molarity = 34.4/180.155 times 1000/555 = 0.19095 times 1.8018 = 0.344 rightarrow Molarity of the glucose solution is 0.344 m Weight of glucose w_g/u = 36.4 ug rightarrow M.wt of glucose Mwt = 180.155 g/mol rightarrow weight at solvent W = 482 g Molarity = w/M.wt times 1000/W_g = 36.4/180.155 times 1000/482 = 0.2020 times 2.0747 = 0.41908 Molarity of glucose solution is 0.41908 m concentration of pb = 10^-6 g concentration Blood = 10^-1 Liter = 10^-1 times 10^3 ml = 10^2 ml 1 ml = 1g = 10^2 g concentration of Blood = 10^2 g concentration in ppm = Amount of pb/Amount of blood times 10^6