Two particles approach each other with equal and opposite speed, v. The mass of one particle...

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Two particles approach each other with equal and opposite speed, v. The mass of one particle is m, and the mass of the other

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Answer 1

Answer #1

final velocity of m1

v1 = (m1 - m2) u1 / ( m1 + m2) + 2 m2 u2 / ( m1 + m2)

0.75v = ( m - nm) v / ( m + nm) - 2 nm * v / ( m + nm)

0.75* ( 1 + n) = 1 - n - 2n

0.75 + 0.75n = 1 - 3n

n = 0.067

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Answer 2

Answer #2

Apply the law of conservation of momentum. mv-nmv=-m(0.750) v+nmv, v-nv+(0.750)v=nv (1.750-n)v Apply the law of conservation

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Answer 3

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Two particles approach each other with equal and opposite speed, v. The mass of one particle...

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