Question

Figure P15.30 shows the electric field lines for t Problem 30 only
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Answer #1

(30) a. The number of lines crossing a surface which is proportional to the electric flux through that surface.

\Phi = \alpha N

We can find the ratio of electric flux through two surfaces by dividing the numbers of lines crossing the surfaces.

Then, we have

\Phi1 / \Phi2 = \alpha N1 / \alpha N2

\Phi1 / \Phi2 = N1 / N2

From gauss law, the electric flux through a gaussian surface is proportional to the net charge enclosed by the surface. Therefore, the ratio of q1 / q2 will be given as :

q1 / q2 = - \varepsilon0\Phi1 / \varepsilon0\Phi2

q1 / q2 = - N1 / N2

q1 / q2 = - (6 / 18)

q1 / q2 = - 1 / 3

b. The direction of an electric field lines at each point coincides with the direction of an electric field vector. Therefore, they originate on a positive charge & terminate on negative charge.

The signs of charge q1 will be negative while a charge q2 will be positive.

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