From the given data we have
s = 1.9126
s^2 = 3.6582
a)
chi square value for lower bound = 23.5894
chi square value for upper bound = 1.7349
CI = ((10 - 1)*3.6582/23.5894, (10 - 1)*3.6582/1.7349)
= (1.3956, 18.9762)
b)
(10 - 1)*3.6582/23.5894 = 1.3956
1.3956 <= sigma^2
c)
chi square value for lower bound = 16.9190
(10 - 1)*3.6582/16.9190 = 1.9459
1.9459 <= sigma^2
Help! nment FULL SCREEN PRINTER VERSION BACK Question 5 An article in the Australian Journal of...