HCl + NaOH --------> NaCl + H2O
millimoles of HCL = 31.0 x 0.310 = 9.61
a) millimoles of NaOH added = 41.0 x 0.310 = 12.71
12.71 - 9.61 = 3.1 millimoles NaOH left
[NaOH] = 3.1 / 31+41 = 0.043 M
[OH-] = [NaOH] = 0.043 M
pOH = - log [OH-]
pOH = - log [0.043]
pOH = 1.37
pH = 14 - 1.37
pH = 12.63
b) millimoles of NaOH = 21 x0 .410 = 8.61
9.61 - 8.61 = 1.0 millimoles HCl left
[HCl] = 1.0 / 31 + 21 = 0.019 M
[H+] = [HCl] = 0.019 M
pH = - log [H+]
pH = - log [0.019]
pH = 1.72
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