Question

How much heat is required to change steam at 130 degrees Celsius to ice at 20 degrees Celsius?

Answer 1

Net heat required

Q = heat required to change the temp of stem

+ heat required to change vapour to water

+ heat required to change temp from + 100 to 0

+ heat required to change state from water to ice

+ heat required to change temp of water from 0 to - 20

Q = m ( Cs * (130 - 100) + Lv + Cw ( 100-0) + Lf + Ci ( 20-0))

Q = m ( 2000 * 30 + 2260* 1000 + 4186* 100 + 3.36* 10^5 + 2.108* 1000* 20)

Q = (3.12 x 10^6) m

NOTE: as the value of the mass of steam isn't given in the problem, so the final expression provided above is in terms of mass "m", just put the value of mass (m) and get the desired result or you can provide me its value in comments section below.

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