Question

The radius of the aorta is about 1.1 cm , and the blood passing through it has a speed of about 48 cm/s . Coefficient of viscosity for the whole blood (37∘) is η = 4×10−3Pa⋅s.Calculate the pressure drop per cm along the aorta.

Answer 1

Pressure drop is given by

$Q = \frac{\delta P \pi r^4}{8\eta l}$

$\pi r^2 v = \frac{\delta P \pi r^4}{8\eta l}$

Plug in all values we will have

$P = 1.27*10^5 Pa$