A 100 g aluminum calorimeter contains 250 g of water. The two substances are in thermal equilibrium at 10°C. Two metallic blocks are placed in the water. One is a 50 g piece of copper at 76°C. The other sample has a mass of 73 g and is originally at a temperature of 100°C. The entire system stabilizes at a final temperature of 20°C. Determine the specific heat of the unknown second sample.
J/kg·°C
mAl = 100 g, mw = 250 g, mcu = 50 g,m = 73 g,
specific heat capacity of water = 4186 J/kg.oC
specific heat capacity of Al = 900 J/kg.oC
specific heat capacity of copper = 387 J/kg.oC
Energy gain by system = energy lost by system
mA1Cp*(T2-T1) +mw*Cp(T2-T1) = -mcu*Cp*(T2-T1) -
m*C*(T2-T1)
100*900*(20-10)+250*4186*(20-10) = -50*387*(20-76)
-73*C*(20-100)
specific heat capacity of unkonwn material C = 1760 J/kg.oC
A 100 g aluminum calorimeter contains 250 g of water. The two substances are in thermal...
A
100 g aluminum calorimeter contains 250 g of water. The two
substances are in thermal equilibrium at 10°C. Two metallic blacks
are placed in water. One is a 50 gram piece of copper at 82°C. The
other sample has a mass of 57 g and is originally at a temperature
of 100°C. The entire system stabilizes at a final temperature of
20°C. Determine the specific heat of the unknown second sample.
A 100 g aluminum calorimeter contains 250 g...
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