Question

Specify the formal charges (both sign and magnitude) on the atoms labeled a-c. HC- HO: Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

ANSWER

Q. 1

a b c

0 0 0

Q. 2

a b c

-1 +1 -1

F.C = [ Total no. of valence electrons in the free atom ] - [ total no. of non bonding electrons ( lone pair ) ] - 1/2 [ total no. of bonding electrons ]

Question 1

Calculation of F.C on C atom labelled a.

Total no. of valence electrons in the free C atom = 4

Total no. of non bonding electrons = 0

Total no. of bonding electrons = 8

$\therefore$ F.C on C atom labelled a = 4 - 0 - 1/2 (8) = 0

Calculation of F.C on C atom labelled b.

Total no. of valence electrons in the free C atom = 4

Total no. of non bonding electrons = 0

Total no. of bonding electrons = 8

$\therefore$ F.C on C atom labelled b = 4 - 0 - 1/2 (8) = 0

Calculation of F.C on C atom labelled C.

Total no. of valence electrons in the free C atom = 4

Total no. of non bonding electrons = 2

Total no. of bonding electrons =4

$\therefore$ F.C on C atom labelled C = 4 - 2 - 1/2 (4) = 0  

Question 2

Calculation of F.C on C atom labelled a.

Total no. of valence electrons in the free C atom = 4

Total no. of non bonding electrons = 2

Total no. of bonding electrons =6

$\therefore$ F.C on C atom labelled a = 4 - 2 - 1/2 (6) = - 1

Calculation of F.C on N atom labelled b.

Total no. of valence electrons in the free N atom = 5

Total no. of non bonding electrons = 0

Total no. of bonding electrons = 8

$\therefore$ F.C on N atom labelled b = 5 - 0 - 1/2 (8) = + 1

Calculation of F.C on O atom labelled C.

Total no. of valence electrons in the free O atom =6

Total no. of non bonding electrons = 6  

Total no. of bonding electrons =2

$\therefore$ F.C on O atom labelled C = 6 - 6 - 1/2 (2) = - 1