Question

Write an application that can be used to determie if three line segments can form a triangle. Prompt the user for the length of three line segments as integers. If non-numeric characters are entered, re-prompt the user for the new values. If the three lines could form a triangle, print the integers and a message indicating that they form a triangle. Use a state-controlled loop to allow users to enter as many different combinations as they want.

Answer 1

Enter the lengths of triangle here: Enter length of side 1: -7 Enter length of side 2 8 Enter length of side 3 2 Invalid lengths. Please try again. Enter the lengths of triangle here: Enter length of side 1 : 5 Enter length of side 26 Enter length of side 3 3 Given lengths of sides can make a triangle.

Editable code:

#include <stdio.h>

#include <stdlib.h>

int main()

{ int i , a, b, c, r;

float p;

char ch;

while(1){

printf("\nEnter the Lengths of triangle here :\n");

printf("Enter Length of side 1 : ");

scanf("%d", &a);

printf("\nEnter Length of side 2 : ");

scanf("%d", &b);

printf("\nEnter Length of side 3 : ");

scanf("%d", &c);

if(a<=0 || b<=0 || c<=0){

printf("\nInvalid lengths. Please try again.");

continue;

}

p = (float)(a+b+c)/2.0f;

r=p*(p-a)*(p-b)*(p-c);

if(r<=0){

printf("\n\n\n Given lengths of sides can not make a triangle.");

}

else {

printf("\n\n\n Given lengths of sides can make a triangle.");

}

printf("\n\n do you want to try another values ? (Y/N):");

scanf(" %c", &ch);

if(ch == 'N'){

break;

}

printf("\n\n------------------------------------------------\n\n");

}

return 0;

}