Use boolean algebra to reduce; qm+q!p+q!m+!q!m+!mp
qm+q!p+q!m+!q!m+!mp =qm+q!m+q!p+q!m+!q!m+!mp = qm+q!m+q!p+(q+!q)!m+!mp = qm+q!m+q!p+(1)!m+!mp = qm+q!m+q!p+!m+!mp = qm+q!m+q!p+!m(1+p) = qm+q!m+q!p+!m(1) = qm+q!m+q!p+!m = q(m+!m)+q!p+!m = q(1)+q!p+!m = q+q!p+!m = q(1+!p)+!m = q(1)+!m = q+!m
Use the properties of Boolean Algebra to reduce the following Boolean expression to the simplest form possible B’A+(B’+A)B
Reduce the following equation using Boolean algebra and show all of your steps. Q = A'B'C'D' + A'B'C'D + A'B'CD' + AB'C'D' + AB'C'D + AB'CD' + AB'CD
Reduce the following equation using Boolean algebra and show all of your steps. Q = A'B'C'D' + A'B'C'D + A'B'CD' + AB'C'D' + AB'C'D+AB'CD' + AB'CD
Discrete Math:
Decide whether (p^q)r and
(pr)^(qr) are
logically equivalent using boolean algebra. Show work! Do NOT use
truth table.
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2. Suppose P and Q are positive odd integers such that (PQ)-1. Prove that Qm] Pn] P-1 0-1 0<m<P/2 0<n
Reduce the following equation using Boolean algebra and show all of your steps. 0 - A'B'C + A'BC' + A'BC + ABC
How to simplify boolean algebra and check for equivalent
equations?
Boolean Algebra 13. Select the Boolean expressions that share the same truth table as A-B-C+A-B-C+A-B-C+A-B-C Select all that apply. O A. ĀB.C+A-B-T+A-B-C+A-B-C O B. (A+B+C).(A+B+C)-(A+B+C) A+B+C) O C. (A+B+C). (A+B+C)-(A+B+C). (A+B+C) O D . (A+B+C) A+B+C).(A+B+C) (A+B+C) O E. (1+B+C)(A+B+C). (A+B+C)-(A+B+C) 14. Select all equivalent Boolean equations. O A. B+AC OB. AB+AC + BC + BC O c. (+B)A+C)(B+C)(B+C) OD. AB+AC+C 15. Select the Boolean expression(s) matching the filled areas...
Use Boolean algebra to simplify. a = (NOT B) * (NOT C + NOT A) * (NOT G + (NOT D + NOT A)) * (NOT H + ((NOT E + NOT A)*(NOT F + (NOT D + NOT A)))
Let ? be a Boolean algebra and ?,? two elements of ?. Use properties of Boolean algebras to find the solution of the equation (i.e., solve for ?x) a⋅x+b¯=0 in term of ?a and ?b according to conditions in each item. a) What is the solution set of the equation above if ?=1a=1 and ?=1b=1? Justify your answer. b) What is the solution set of the equation above if ?=1a=1 and ?=0b=0? Justify your answer.
Simplify the Boolean expression (P ∧ Q ∧ ~R) ∨ (~P ∧ Q ∧ R) ∨ (~P ∧ ~Q ∧ R) could you also list the laws you used?