Consider two cells, the first with Al and Ag electrodes, and the second with Zn and...
Question 15 of 15 incorrect ncorech incorrect incorrect incorrect Consider two oeils, the first with AIand Ag electrodes, and the second with Zn and Ni electrodes, each in appropriate 100 M solutions oftheir ons a)rt connected as voitaic cells in series, which two metals are plated, and what is the total potential? Al(s) Number Ag(s Ni(s b) If connected such that one cell acts as a battery to power the other as an electrolytic cell, which two metals are plated,...
Two electrolytic cells are connected in series and the same current flows through both. In one cell Ag+ ions are reduced to Ag(s); in the other cell Cr6+ ions are reduced to Cr(s). If 100 g of silver metal are plated out in the silver cell, what mass, in g, of Cr(s) will be deposited in the other cell? A. 48.2 B. 207 C. 4.0 D.16.1 E.8.0
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
Question 3 6.66 pts The following half-cells are availble: (i) Ag (1.0M) 1 Ag (s) (ii) Zn2+ (1.0 M) | Zn (s) (iii) Cu2+ (1.0 M)Cu (s) (iv) Co2+ (1.0 M)Co (s) 0.7994 v -0.76 V 0.337 v -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode and...
1Given the cell representation: Ag(s) ; Ag+|| Al3+ ; Al(s) , the aluminum is the: A.cathode - B.Salt bridge - C.anode 2The type of cell of which the anode is positive is: A.bacteria - b.voltaic - c. electrolytic 3If the calculated Eocell is positive the cell is voltaic: True/False 4In a gas electrode, the glass compartment and metal, is imersed in a solution containng the ions of the gas: true/false
The following half-cells are availble: (i) Ag+ (1.0 M) ∣ Ag (s) 0.7994 v (ii) Zn2+ (1.0 M) ∣ Zn (s) -0.76 v (iii) Cu2+ (1.0 M) ∣ Cu (s) 0.337 v (iv) Co2+ (1.0 M) ∣ Co (s) -0.28 v Linking any two half-cells makes a voltaic cell. Given four different half-cells, six voltaic cells are possible. These are labeled, for simplicity, Ag - Zn, Ag-Cu, Ag-Co, Zn - Cu, Zn-Co, and Cu-Co. (the first metal is the anode...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Calculate the theoretical cell potential (E°) of a galvanic cell under standard conditions made up of copper and magnesium (see Part II and Table 1 for more information). PARTIL Creating and Testing Voltaic Cells Introduction and Background for the Voltaic Cells A galvanic cell (sometimes more appropriately called a voltaic cell) consists of two half-cells joined by a salt bridge that allow ions to pass between the two sides in order to maintain electroneutrality. Each half-cell contains the Components of...
2. Answer the following questions having to do with voltaic and electrolytic cells. A) Use the standard reduction potentials below to write the cell reaction the would produce the greatest potential in a voltaic cell. B) Cd^2+ (aq) + 2e- -> Cd (s) E = -.402 V Tl+ (aq) + e- -> Tl (s) E = -.336 V Cu^2+ (aq) + e- -> Cu+ (aq) E = +.161 V B1) For the galvanic cell based on the reaction above, calculate...