Homework Answers
(a)
Molarity = (mass / molar mass) * (1000 / Volume of solution in L)
0.1 = (mass / 101.1) * (1000 / 300)
Mass of KNO3 = 3.03 g.
KNO3 (aq.) --------------> K+ (aq.) + NO3- (aq.)
[K+] = [KNO3] = 01. M initial
Intial moles of K+ ions = 0.1 * 300 / 1000 = 0.0300 mol
(b)
Moles of K2SO4 added = 10 / 174.3 = 0.0574 mol
K2SO4 (s) --------------> 2 K+ (aq.) + SO42- (aq.)
Moles K+ = 2 * moles of K2SO4 = 2 * 0.0574 = 0.115 mol
Therefore, total moles of K+ ions = 0.0300 + 0.115= 0.145 mol
Therefore, new [K+] = 0.145 * 1000 / 300 = 0.483 M
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