A piece of aluminum has a density of 2700 kg/m3 and a mass of 0.775 kg....

Question

Question

Answer 1

Answer #1

A) Buoyant force acting on aluminium = weight of the oil displaced

= volume of aluminium x density of oil

= massof aluminium densityofaluminium densityo foil *g

$\frac{0.775}{2700}*650*9.8 = 1.83 N$

B) Apparent weight = weight - buoyant force

$(mass of alluminium -\frac{mass of aluminium}{density of aluminium}density of water)*g$

$(0.775 -\frac{0.775}{2700}*1000)*g$

= 4.78 N

Answer 2

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