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The potassium chlorate (KClO3, 122.55g/mol) in an 0.1862g sample of an explosive was determined by reaction...

The potassium chlorate (KClO3, 122.55g/mol) in an 0.1862g sample of an explosive was determined by reaction with 50.00mL of 0.01162M Fe2+ in the following reaction:

ClO3- + 6Fe2+ + 6H+ --> Cl- + 3H2O + 6Fe3+.

Calculate the percentage of KClO3 in the original sample.

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Answer #1

I ODO ml itu no mols k,(o.contR) 6 mol. ニ1 o.ola qui

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